时间:2007-12-17 22:43
人气:
作者:admin
ug渐开线直齿轮C方程序如下:
/* HELLO.C -- Hello, world */
#include "stdio.h"
#include "math.h"
struct jkx_type
{
float x;
float y;
float zz;
} jkx[6];
/*x=r(cos(theta)+theta*sin(theta))
y=r(sin(theta)-theta*cos(theta))
x=r(cost+tsint),y=r(sint-tcost) */
main()
{ FILE *fp;
int i;
float j=0,z,m,rb,u,a;
char * filename;
printf("%s\n","filename");
scanf("%s",filename);
if((fp=fopen(filename,"w"))==NULL)
{
printf("error!");
exit(0);
}
printf("%s\n","m=");
scanf("%f",&m);
printf("%s\n","z=");
scanf("%f",&z);
printf("%s\n","a=");
scanf("%f",&a);
a=(a/180)*3.1415926;
rb=0.5*m*z*cos(a);
for(i=0;i<6;i++)
{
u=(j/180)*3.1415926;
jkx[i].x=rb*(sin(u)-u*cos(u));
jkx[i].y=rb*(cos(u)+u*sin(u));
jkx[i].zz=0;
fprintf(fp,"%f %f %f ",jkx[i].x,jkx[i].y,jkx[i].zz);
fprintf(fp,"\n");
printf("%f %f %f \n",jkx[i].x,jkx[i].y,jkx[i].zz);
j=j+10;
}
fclose(fp);
getch();
}
/* a=0
b=360
m=0.7
r=m*z*cos(20)/2
s=(1-t)*a+t*b
t=1
xt=r*cos(s)+r*rad(s)*sin(s)
yt=r*sin(s)-r*rad(s)*cos(s)
z=15
zt=0 */
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